Base | Representation |
---|---|
bin | 100000011110111010001… |
… | …101111011011100000011 |
3 | 21220101201201010212210021 |
4 | 200132322031323130003 |
5 | 243033032313141011 |
6 | 4425244131114311 |
7 | 320162204656426 |
oct | 40367215733403 |
9 | 7811651125707 |
10 | 2232212240131 |
11 | 790748685845 |
12 | 30074b442997 |
13 | 13265c374363 |
14 | 7a07ab219bd |
15 | 3d0e93b4471 |
hex | 207ba37b703 |
2232212240131 has 2 divisors, whose sum is σ = 2232212240132. Its totient is φ = 2232212240130.
The previous prime is 2232212240119. The next prime is 2232212240149. The reversal of 2232212240131 is 1310422122322.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2232212240131 - 25 = 2232212240099 is a prime.
It is a super-3 number, since 3×22322122401313 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 2232212240096 and 2232212240105.
It is not a weakly prime, because it can be changed into another prime (2232212250131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1116106120065 + 1116106120066.
It is an arithmetic number, because the mean of its divisors is an integer number (1116106120066).
Almost surely, 22232212240131 is an apocalyptic number.
2232212240131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2232212240131 is an equidigital number, since it uses as much as digits as its factorization.
2232212240131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 2232212240131 its reverse (1310422122322), we get a palindrome (3542634362453).
The spelling of 2232212240131 in words is "two trillion, two hundred thirty-two billion, two hundred twelve million, two hundred forty thousand, one hundred thirty-one".
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