Base | Representation |
---|---|
bin | 1100111111111110010… |
… | …1010011001100010001 |
3 | 210100110100020112101211 |
4 | 3033333211103030101 |
5 | 12124340303100423 |
6 | 250332540500121 |
7 | 22064233505065 |
oct | 3177745231421 |
9 | 710410215354 |
10 | 223331300113 |
11 | 86794773309 |
12 | 3734924a641 |
13 | 180a1c17abc |
14 | ab489adaa5 |
15 | 5c218c710d |
hex | 33ff953311 |
223331300113 has 2 divisors, whose sum is σ = 223331300114. Its totient is φ = 223331300112.
The previous prime is 223331300081. The next prime is 223331300123. The reversal of 223331300113 is 311003133322.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 127697593104 + 95633707009 = 357348^2 + 309247^2 .
It is a cyclic number.
It is not a de Polignac number, because 223331300113 - 25 = 223331300081 is a prime.
It is a super-2 number, since 2×2233313001132 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (223331300123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 111665650056 + 111665650057.
It is an arithmetic number, because the mean of its divisors is an integer number (111665650057).
Almost surely, 2223331300113 is an apocalyptic number.
It is an amenable number.
223331300113 is a deficient number, since it is larger than the sum of its proper divisors (1).
223331300113 is an equidigital number, since it uses as much as digits as its factorization.
223331300113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 22.
Adding to 223331300113 its reverse (311003133322), we get a palindrome (534334433435).
The spelling of 223331300113 in words is "two hundred twenty-three billion, three hundred thirty-one million, three hundred thousand, one hundred thirteen".
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