Base | Representation |
---|---|
bin | 11010101000100… |
… | …00010010111001 |
3 | 120120101120121121 |
4 | 31110100102321 |
5 | 424143212213 |
6 | 34100305241 |
7 | 5351661055 |
oct | 1524202271 |
9 | 516346547 |
10 | 223413433 |
11 | 105124901 |
12 | 629a2221 |
13 | 373942c9 |
14 | 21958c65 |
15 | 1493188d |
hex | d5104b9 |
223413433 has 2 divisors, whose sum is σ = 223413434. Its totient is φ = 223413432.
The previous prime is 223413401. The next prime is 223413461. The reversal of 223413433 is 334314322.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 188980009 + 34433424 = 13747^2 + 5868^2 .
It is a cyclic number.
It is not a de Polignac number, because 223413433 - 25 = 223413401 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 223413398 and 223413407.
It is not a weakly prime, because it can be changed into another prime (223413493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 111706716 + 111706717.
It is an arithmetic number, because the mean of its divisors is an integer number (111706717).
Almost surely, 2223413433 is an apocalyptic number.
It is an amenable number.
223413433 is a deficient number, since it is larger than the sum of its proper divisors (1).
223413433 is an equidigital number, since it uses as much as digits as its factorization.
223413433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5184, while the sum is 25.
The square root of 223413433 is about 14947.0208737394. The cubic root of 223413433 is about 606.7872229857.
Adding to 223413433 its reverse (334314322), we get a palindrome (557727755).
The spelling of 223413433 in words is "two hundred twenty-three million, four hundred thirteen thousand, four hundred thirty-three".
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