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22400011331437 is a prime number
BaseRepresentation
bin1010001011111011010001…
…01101111110011101101101
32221022102100022012102102111
411011331220231332131231
510414000210400101222
6115350231222124021
74501230106524145
oct505755055763555
987272308172374
1022400011331437
11715687847a743
122619332580611
13c6640962301c
145762485bd925
1528ca20749777
hex145f68b7e76d

22400011331437 has 2 divisors, whose sum is σ = 22400011331438. Its totient is φ = 22400011331436.

The previous prime is 22400011331377. The next prime is 22400011331449. The reversal of 22400011331437 is 73413311000422.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 16830760605961 + 5569250725476 = 4102531^2 + 2359926^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-22400011331437 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 22400011331399 and 22400011331408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (22400011338437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11200005665718 + 11200005665719.

It is an arithmetic number, because the mean of its divisors is an integer number (11200005665719).

Almost surely, 222400011331437 is an apocalyptic number.

It is an amenable number.

22400011331437 is a deficient number, since it is larger than the sum of its proper divisors (1).

22400011331437 is an equidigital number, since it uses as much as digits as its factorization.

22400011331437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12096, while the sum is 31.

Adding to 22400011331437 its reverse (73413311000422), we get a palindrome (95813322331859).

The spelling of 22400011331437 in words is "twenty-two trillion, four hundred billion, eleven million, three hundred thirty-one thousand, four hundred thirty-seven".