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2241150433 is a prime number
BaseRepresentation
bin1000010110010101…
…0011110111100001
312210012010020102121
42011211103313201
514042213303213
61010215344241
7106352315164
oct20545236741
95705106377
102241150433
11a50086545
12526682081
1329940ba22
1417390dadb
15d1b4988d
hex85953de1

2241150433 has 2 divisors, whose sum is σ = 2241150434. Its totient is φ = 2241150432.

The previous prime is 2241150419. The next prime is 2241150449. The reversal of 2241150433 is 3340511422.

2241150433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1181778129 + 1059372304 = 34377^2 + 32548^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2241150433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2241150398 and 2241150407.

It is not a weakly prime, because it can be changed into another prime (2241150413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1120575216 + 1120575217.

It is an arithmetic number, because the mean of its divisors is an integer number (1120575217).

Almost surely, 22241150433 is an apocalyptic number.

It is an amenable number.

2241150433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2241150433 is an equidigital number, since it uses as much as digits as its factorization.

2241150433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 25.

The square root of 2241150433 is about 47340.7903715179. The cubic root of 2241150433 is about 1308.6504823242.

Adding to 2241150433 its reverse (3340511422), we get a palindrome (5581661855).

The spelling of 2241150433 in words is "two billion, two hundred forty-one million, one hundred fifty thousand, four hundred thirty-three".