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224121433433 is a prime number
BaseRepresentation
bin1101000010111010101…
…1011010110101011001
3210102111102000110112212
43100232223122311121
512133000041332213
6250543204044505
722122636515552
oct3205653326531
9712442013485
10224121433433
118705a785157
1237529993735
1318199824a01
14abc18cb329
155c6ae509a8
hex342eadad59

224121433433 has 2 divisors, whose sum is σ = 224121433434. Its totient is φ = 224121433432.

The previous prime is 224121433411. The next prime is 224121433453. The reversal of 224121433433 is 334334121422.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 133924525849 + 90196907584 = 365957^2 + 300328^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-224121433433 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 224121433433.

It is not a weakly prime, because it can be changed into another prime (224121433453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 112060716716 + 112060716717.

It is an arithmetic number, because the mean of its divisors is an integer number (112060716717).

Almost surely, 2224121433433 is an apocalyptic number.

It is an amenable number.

224121433433 is a deficient number, since it is larger than the sum of its proper divisors (1).

224121433433 is an equidigital number, since it uses as much as digits as its factorization.

224121433433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 41472, while the sum is 32.

Adding to 224121433433 its reverse (334334121422), we get a palindrome (558455554855).

The spelling of 224121433433 in words is "two hundred twenty-four billion, one hundred twenty-one million, four hundred thirty-three thousand, four hundred thirty-three".