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22413241445117 is a prime number
BaseRepresentation
bin1010001100010011111010…
…10010110110101011111101
32221100200111022222211111212
411012021331102312223331
510414204304302220432
6115400300113254205
74502206005610145
oct506117522665375
987320438884455
1022413241445117
117161447535996
12261ba05264365
13c67737593963
14576b41729925
1528d046ea32b2
hex14627d4b6afd

22413241445117 has 2 divisors, whose sum is σ = 22413241445118. Its totient is φ = 22413241445116.

The previous prime is 22413241445041. The next prime is 22413241445183. The reversal of 22413241445117 is 71154414231422.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18934516607161 + 3478724837956 = 4351381^2 + 1865134^2 .

It is a cyclic number.

It is not a de Polignac number, because 22413241445117 - 28 = 22413241444861 is a prime.

It is a super-2 number, since 2×224132414451172 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (22413241445417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11206620722558 + 11206620722559.

It is an arithmetic number, because the mean of its divisors is an integer number (11206620722559).

Almost surely, 222413241445117 is an apocalyptic number.

It is an amenable number.

22413241445117 is a deficient number, since it is larger than the sum of its proper divisors (1).

22413241445117 is an equidigital number, since it uses as much as digits as its factorization.

22413241445117 is an evil number, because the sum of its binary digits is even.

The product of its digits is 215040, while the sum is 41.

Adding to 22413241445117 its reverse (71154414231422), we get a palindrome (93567655676539).

The spelling of 22413241445117 in words is "twenty-two trillion, four hundred thirteen billion, two hundred forty-one million, four hundred forty-five thousand, one hundred seventeen".