Base | Representation |
---|---|
bin | 1010001100110011100110… |
… | …10000111110110101110011 |
3 | 2221102022101220022222001022 |
4 | 11012121303100332311303 |
5 | 10414444124240120001 |
6 | 115412152131130055 |
7 | 4503350403100403 |
oct | 506316320766563 |
9 | 87368356288038 |
10 | 22430253051251 |
11 | 7168687101411 |
12 | 262317244392b |
13 | c69218abb9a6 |
14 | 5778b6b8a803 |
15 | 28d6e06be11b |
hex | 14667343ed73 |
22430253051251 has 2 divisors, whose sum is σ = 22430253051252. Its totient is φ = 22430253051250.
The previous prime is 22430253051221. The next prime is 22430253051253. The reversal of 22430253051251 is 15215035203422.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 22430253051251 - 234 = 22413073182067 is a prime.
Together with 22430253051253, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (22430253051253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11215126525625 + 11215126525626.
It is an arithmetic number, because the mean of its divisors is an integer number (11215126525626).
Almost surely, 222430253051251 is an apocalyptic number.
22430253051251 is a deficient number, since it is larger than the sum of its proper divisors (1).
22430253051251 is an equidigital number, since it uses as much as digits as its factorization.
22430253051251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72000, while the sum is 35.
Adding to 22430253051251 its reverse (15215035203422), we get a palindrome (37645288254673).
The spelling of 22430253051251 in words is "twenty-two trillion, four hundred thirty billion, two hundred fifty-three million, fifty-one thousand, two hundred fifty-one".
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