Base | Representation |
---|---|
bin | 1010001110110111110011… |
… | …00011100011100101110011 |
3 | 2221200002121002121011020202 |
4 | 11013123321203203211303 |
5 | 10422130002214402201 |
6 | 115504530442025415 |
7 | 4511442226244132 |
oct | 507337143434563 |
9 | 87602532534222 |
10 | 22501225544051 |
11 | 7195797239741 |
12 | 2634a7aaa826b |
13 | c72b19862067 |
14 | 57b0ca9cd919 |
15 | 29049637ac6b |
hex | 1476f98e3973 |
22501225544051 has 2 divisors, whose sum is σ = 22501225544052. Its totient is φ = 22501225544050.
The previous prime is 22501225544029. The next prime is 22501225544101. The reversal of 22501225544051 is 15044552210522.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-22501225544051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 22501225543996 and 22501225544014.
It is not a weakly prime, because it can be changed into another prime (22501225544851) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11250612772025 + 11250612772026.
It is an arithmetic number, because the mean of its divisors is an integer number (11250612772026).
Almost surely, 222501225544051 is an apocalyptic number.
22501225544051 is a deficient number, since it is larger than the sum of its proper divisors (1).
22501225544051 is an equidigital number, since it uses as much as digits as its factorization.
22501225544051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 160000, while the sum is 38.
Adding to 22501225544051 its reverse (15044552210522), we get a palindrome (37545777754573).
The spelling of 22501225544051 in words is "twenty-two trillion, five hundred one billion, two hundred twenty-five million, five hundred forty-four thousand, fifty-one".
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