Base | Representation |
---|---|
bin | 100000110000110101100… |
… | …010010101001101001011 |
3 | 21222020102012012000011212 |
4 | 200300311202111031023 |
5 | 243341443012232212 |
6 | 4442150144043335 |
7 | 321443206131212 |
oct | 40606542251513 |
9 | 7866365160155 |
10 | 2251461055307 |
11 | 798926085562 |
12 | 30442190354b |
13 | 13440922b119 |
14 | 7ad85348079 |
15 | 3d8741ebe22 |
hex | 20c3589534b |
2251461055307 has 2 divisors, whose sum is σ = 2251461055308. Its totient is φ = 2251461055306.
The previous prime is 2251461055279. The next prime is 2251461055309. The reversal of 2251461055307 is 7035501641522.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2251461055307 is a prime.
It is a super-2 number, since 2×22514610553072 (a number of 26 digits) contains 22 as substring.
Together with 2251461055309, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2251461055309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1125730527653 + 1125730527654.
It is an arithmetic number, because the mean of its divisors is an integer number (1125730527654).
Almost surely, 22251461055307 is an apocalyptic number.
2251461055307 is a deficient number, since it is larger than the sum of its proper divisors (1).
2251461055307 is an equidigital number, since it uses as much as digits as its factorization.
2251461055307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252000, while the sum is 41.
Adding to 2251461055307 its reverse (7035501641522), we get a palindrome (9286962696829).
The spelling of 2251461055307 in words is "two trillion, two hundred fifty-one billion, four hundred sixty-one million, fifty-five thousand, three hundred seven".
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