Base | Representation |
---|---|
bin | 1101000110111100001… |
… | …1101011010010110101 |
3 | 210112021200102021011111 |
4 | 3101233003223102311 |
5 | 12142203043043013 |
6 | 251242310235021 |
7 | 22161463312312 |
oct | 3215703532265 |
9 | 715250367144 |
10 | 225201534133 |
11 | 87564438864 |
12 | 3778b655a71 |
13 | 1830c529054 |
14 | ac85129d09 |
15 | 5cd0ba573d |
hex | 346f0eb4b5 |
225201534133 has 2 divisors, whose sum is σ = 225201534134. Its totient is φ = 225201534132.
The previous prime is 225201534121. The next prime is 225201534143. The reversal of 225201534133 is 331435102522.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 213302651409 + 11898882724 = 461847^2 + 109082^2 .
It is a cyclic number.
It is not a de Polignac number, because 225201534133 - 25 = 225201534101 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 225201534095 and 225201534104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (225201534143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 112600767066 + 112600767067.
It is an arithmetic number, because the mean of its divisors is an integer number (112600767067).
Almost surely, 2225201534133 is an apocalyptic number.
It is an amenable number.
225201534133 is a deficient number, since it is larger than the sum of its proper divisors (1).
225201534133 is an equidigital number, since it uses as much as digits as its factorization.
225201534133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 225201534133 its reverse (331435102522), we get a palindrome (556636636655).
The spelling of 225201534133 in words is "two hundred twenty-five billion, two hundred one million, five hundred thirty-four thousand, one hundred thirty-three".
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