Base | Representation |
---|---|
bin | 1010010000000000000010… |
… | …11110110011010100011011 |
3 | 2221210210201021110022100221 |
4 | 11020000001132303110123 |
5 | 10423243421341034042 |
6 | 115534423352340511 |
7 | 4514314353123622 |
oct | 510000136632433 |
9 | 87723637408327 |
10 | 22540013221147 |
11 | 7200190934624 |
12 | 26404a49a4737 |
13 | c7668b6c7196 |
14 | 57cd2a1806b9 |
15 | 2914b66e0d67 |
hex | 1480017b351b |
22540013221147 has 2 divisors, whose sum is σ = 22540013221148. Its totient is φ = 22540013221146.
The previous prime is 22540013221079. The next prime is 22540013221247. The reversal of 22540013221147 is 74112231004522.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 22540013221147 - 223 = 22540004832539 is a prime.
It is not a weakly prime, because it can be changed into another prime (22540013221247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11270006610573 + 11270006610574.
It is an arithmetic number, because the mean of its divisors is an integer number (11270006610574).
Almost surely, 222540013221147 is an apocalyptic number.
22540013221147 is a deficient number, since it is larger than the sum of its proper divisors (1).
22540013221147 is an equidigital number, since it uses as much as digits as its factorization.
22540013221147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26880, while the sum is 34.
Adding to 22540013221147 its reverse (74112231004522), we get a palindrome (96652244225669).
The spelling of 22540013221147 in words is "twenty-two trillion, five hundred forty billion, thirteen million, two hundred twenty-one thousand, one hundred forty-seven".
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