Base | Representation |
---|---|
bin | 1101000111101110111… |
… | …1100000100010110111 |
3 | 210112211111212111001211 |
4 | 3101323233200202313 |
5 | 12143122033213111 |
6 | 251315351502251 |
7 | 22166656240612 |
oct | 3217357404267 |
9 | 715744774054 |
10 | 225414351031 |
11 | 876635852a1 |
12 | 3782a987987 |
13 | 183446500cc |
14 | aca54c7179 |
15 | 5ce46e2521 |
hex | 347bbe08b7 |
225414351031 has 2 divisors, whose sum is σ = 225414351032. Its totient is φ = 225414351030.
The previous prime is 225414351017. The next prime is 225414351037. The reversal of 225414351031 is 130153414522.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 225414351031 - 211 = 225414348983 is a prime.
It is a super-2 number, since 2×2254143510312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 225414350984 and 225414351002.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (225414351037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 112707175515 + 112707175516.
It is an arithmetic number, because the mean of its divisors is an integer number (112707175516).
Almost surely, 2225414351031 is an apocalyptic number.
225414351031 is a deficient number, since it is larger than the sum of its proper divisors (1).
225414351031 is an equidigital number, since it uses as much as digits as its factorization.
225414351031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 225414351031 its reverse (130153414522), we get a palindrome (355567765553).
The spelling of 225414351031 in words is "two hundred twenty-five billion, four hundred fourteen million, three hundred fifty-one thousand, thirty-one".
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