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225489271351 is a prime number
BaseRepresentation
bin1101001000000000110…
…1010011101000110111
3210120000201211211102111
43102000031103220313
512143300223140401
6251331025351451
722201556116321
oct3220015235067
9716021754374
10225489271351
11876a18a7013
123784ba98587
1318357022366
14acb142a611
155ceb090e51
hex3480353a37

225489271351 has 2 divisors, whose sum is σ = 225489271352. Its totient is φ = 225489271350.

The previous prime is 225489271327. The next prime is 225489271361. The reversal of 225489271351 is 153172984522.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 225489271351 - 211 = 225489269303 is a prime.

It is a super-2 number, since 2×2254892713512 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 225489271295 and 225489271304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (225489271361) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 112744635675 + 112744635676.

It is an arithmetic number, because the mean of its divisors is an integer number (112744635676).

Almost surely, 2225489271351 is an apocalyptic number.

225489271351 is a deficient number, since it is larger than the sum of its proper divisors (1).

225489271351 is an equidigital number, since it uses as much as digits as its factorization.

225489271351 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1209600, while the sum is 49.

The spelling of 225489271351 in words is "two hundred twenty-five billion, four hundred eighty-nine million, two hundred seventy-one thousand, three hundred fifty-one".