Base | Representation |
---|---|
bin | 10101011010111110… |
… | …000001010010001111 |
3 | 2012100222112002211122 |
4 | 111122332001102033 |
5 | 334101231402421 |
6 | 14322212111155 |
7 | 1442662435433 |
oct | 253276012217 |
9 | 65328462748 |
10 | 23001044111 |
11 | 9833542971 |
12 | 455b0054bb |
13 | 2227366496 |
14 | 1182ac09c3 |
15 | 8e94692ab |
hex | 55af8148f |
23001044111 has 4 divisors (see below), whose sum is σ = 24211625400. Its totient is φ = 21790462824.
The previous prime is 23001044107. The next prime is 23001044113. The reversal of 23001044111 is 11144010032.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 23001044111 - 22 = 23001044107 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 23001044111.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23001044113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 605290616 + ... + 605290653.
It is an arithmetic number, because the mean of its divisors is an integer number (6052906350).
Almost surely, 223001044111 is an apocalyptic number.
23001044111 is a deficient number, since it is larger than the sum of its proper divisors (1210581289).
23001044111 is a wasteful number, since it uses less digits than its factorization.
23001044111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1210581288.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 23001044111 its reverse (11144010032), we get a palindrome (34145054143).
The spelling of 23001044111 in words is "twenty-three billion, one million, forty-four thousand, one hundred eleven".
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