Base | Representation |
---|---|
bin | 110100010011000111011001… |
… | …011010111100000001000011 |
3 | 1010011101221020221101012112211 |
4 | 310103013121122330001003 |
5 | 220122004120004221011 |
6 | 2133110022441402551 |
7 | 66306551362365064 |
oct | 6423073132740103 |
9 | 1104357227335484 |
10 | 230012031320131 |
11 | 6731a611308285 |
12 | 21969a57a99457 |
13 | 9b460701aa768 |
14 | 40b28dac2256b |
15 | 1b8d21a223b21 |
hex | d131d96bc043 |
230012031320131 has 2 divisors, whose sum is σ = 230012031320132. Its totient is φ = 230012031320130.
The previous prime is 230012031320129. The next prime is 230012031320189. The reversal of 230012031320131 is 131023130210032.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 230012031320131 - 21 = 230012031320129 is a prime.
It is a super-2 number, since 2×2300120313201312 (a number of 30 digits) contains 22 as substring.
Together with 230012031320129, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (230012031321131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115006015660065 + 115006015660066.
It is an arithmetic number, because the mean of its divisors is an integer number (115006015660066).
Almost surely, 2230012031320131 is an apocalyptic number.
230012031320131 is a deficient number, since it is larger than the sum of its proper divisors (1).
230012031320131 is an equidigital number, since it uses as much as digits as its factorization.
230012031320131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 230012031320131 its reverse (131023130210032), we get a palindrome (361035161530163).
The spelling of 230012031320131 in words is "two hundred thirty trillion, twelve billion, thirty-one million, three hundred twenty thousand, one hundred thirty-one".
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