Base | Representation |
---|---|
bin | 110100010011000111100110… |
… | …000111011001111000101111 |
3 | 1010011101221210210010212200022 |
4 | 310103013212013121320233 |
5 | 220122010034020202112 |
6 | 2133110055530352355 |
7 | 66306556556615426 |
oct | 6423074607317057 |
9 | 1104357723125608 |
10 | 230012244303407 |
11 | 6731a710558815 |
12 | 21969ab728b6bb |
13 | 9b460a535c477 |
14 | 40b291b2242bd |
15 | 1b8d22dc94d72 |
hex | d131e61d9e2f |
230012244303407 has 2 divisors, whose sum is σ = 230012244303408. Its totient is φ = 230012244303406.
The previous prime is 230012244303403. The next prime is 230012244303481. The reversal of 230012244303407 is 704303442210032.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 230012244303407 - 22 = 230012244303403 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (230012244303403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115006122151703 + 115006122151704.
It is an arithmetic number, because the mean of its divisors is an integer number (115006122151704).
Almost surely, 2230012244303407 is an apocalyptic number.
230012244303407 is a deficient number, since it is larger than the sum of its proper divisors (1).
230012244303407 is an equidigital number, since it uses as much as digits as its factorization.
230012244303407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96768, while the sum is 35.
Adding to 230012244303407 its reverse (704303442210032), we get a palindrome (934315686513439).
The spelling of 230012244303407 in words is "two hundred thirty trillion, twelve billion, two hundred forty-four million, three hundred three thousand, four hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •