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23004040121 is a prime number
BaseRepresentation
bin10101011011001001…
…011100101110111001
32012101012011022120222
4111123021130232321
5334103013240441
614322400225425
71443030054236
oct253311345671
965335138528
1023004040121
1198351a9907
12456000b275
132227b7507a
14118326078d
158e985bd4b
hex55b25cbb9

23004040121 has 2 divisors, whose sum is σ = 23004040122. Its totient is φ = 23004040120.

The previous prime is 23004040091. The next prime is 23004040123. The reversal of 23004040121 is 12104040032.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22858113721 + 145926400 = 151189^2 + 12080^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-23004040121 is a prime.

Together with 23004040123, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 23004040121.

It is not a weakly prime, because it can be changed into another prime (23004040123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11502020060 + 11502020061.

It is an arithmetic number, because the mean of its divisors is an integer number (11502020061).

Almost surely, 223004040121 is an apocalyptic number.

It is an amenable number.

23004040121 is a deficient number, since it is larger than the sum of its proper divisors (1).

23004040121 is an equidigital number, since it uses as much as digits as its factorization.

23004040121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 17.

Adding to 23004040121 its reverse (12104040032), we get a palindrome (35108080153).

The spelling of 23004040121 in words is "twenty-three billion, four million, forty thousand, one hundred twenty-one".