Base | Representation |
---|---|
bin | 100001011110100010010… |
… | …101110110111110000111 |
3 | 22010221001222012201021221 |
4 | 201132202111312332013 |
5 | 300142441433030120 |
6 | 4520503250221211 |
7 | 325131210032053 |
oct | 41364225667607 |
9 | 8127058181257 |
10 | 2300531142535 |
11 | 80771694535a |
12 | 311a37284807 |
13 | 138c294300b2 |
14 | 7d4bc372c63 |
15 | 3ec971070aa |
hex | 217a2576f87 |
2300531142535 has 32 divisors (see below), whose sum is σ = 2830591526400. Its totient is φ = 1793966149248.
The previous prime is 2300531142451. The next prime is 2300531142571. The reversal of 2300531142535 is 5352411350032.
It is a cyclic number.
It is not a de Polignac number, because 2300531142535 - 221 = 2300529045383 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2300531142535.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 463160622 + ... + 463165588.
It is an arithmetic number, because the mean of its divisors is an integer number (88455985200).
Almost surely, 22300531142535 is an apocalyptic number.
2300531142535 is a deficient number, since it is larger than the sum of its proper divisors (530060383865).
2300531142535 is a wasteful number, since it uses less digits than its factorization.
2300531142535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8967.
The product of its (nonzero) digits is 54000, while the sum is 34.
Adding to 2300531142535 its reverse (5352411350032), we get a palindrome (7652942492567).
The spelling of 2300531142535 in words is "two trillion, three hundred billion, five hundred thirty-one million, one hundred forty-two thousand, five hundred thirty-five".
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