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23006444848433 is a prime number
BaseRepresentation
bin1010011101100100110101…
…11110010000010100110001
310000110101122200212000002222
411032302122332100110301
511003414144340122213
6120533003113050425
74563106102416404
oct516623276202461
9100411580760088
1023006444848433
11736aa84381832
1226b69779b6a15
13cab6630c4607
1459773707dd3b
1529d6b52d4808
hex14ec9af90531

23006444848433 has 2 divisors, whose sum is σ = 23006444848434. Its totient is φ = 23006444848432.

The previous prime is 23006444848393. The next prime is 23006444848459. The reversal of 23006444848433 is 33484844460032.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22145617163569 + 860827684864 = 4705913^2 + 927808^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-23006444848433 is a prime.

It is not a weakly prime, because it can be changed into another prime (23006444848133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11503222424216 + 11503222424217.

It is an arithmetic number, because the mean of its divisors is an integer number (11503222424217).

Almost surely, 223006444848433 is an apocalyptic number.

It is an amenable number.

23006444848433 is a deficient number, since it is larger than the sum of its proper divisors (1).

23006444848433 is an equidigital number, since it uses as much as digits as its factorization.

23006444848433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21233664, while the sum is 53.

The spelling of 23006444848433 in words is "twenty-three trillion, six billion, four hundred forty-four million, eight hundred forty-eight thousand, four hundred thirty-three".