Base | Representation |
---|---|
bin | 100001011111000000010… |
… | …000010010110001110010 |
3 | 22010222100221112201101022 |
4 | 201133000100102301302 |
5 | 300200003422000200 |
6 | 4521025134535442 |
7 | 325146512533361 |
oct | 41370020226162 |
9 | 8128327481338 |
10 | 2301033000050 |
11 | 807954160334 |
12 | 311b57367582 |
13 | 138ca93b57c5 |
14 | 7d528c8d7d8 |
15 | 3ecc61da885 |
hex | 217c0412c72 |
2301033000050 has 48 divisors (see below), whose sum is σ = 4381011903840. Its totient is φ = 898688528640.
The previous prime is 2301033000023. The next prime is 2301033000067. The reversal of 2301033000050 is 500003301032.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 2301032999992 and 2301033000028.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5902061 + ... + 6279839.
It is an arithmetic number, because the mean of its divisors is an integer number (91271081330).
Almost surely, 22301033000050 is an apocalyptic number.
2301033000050 is a deficient number, since it is larger than the sum of its proper divisors (2079978903790).
2301033000050 is a wasteful number, since it uses less digits than its factorization.
2301033000050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 380667 (or 380662 counting only the distinct ones).
The product of its (nonzero) digits is 270, while the sum is 17.
Adding to 2301033000050 its reverse (500003301032), we get a palindrome (2801036301082).
The spelling of 2301033000050 in words is "two trillion, three hundred one billion, thirty-three million, fifty", and thus it is an aban number.
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