Base | Representation |
---|---|
bin | 110100010100011110011000… |
… | …011011000001010010100111 |
3 | 1010011201212100001122222112211 |
4 | 310110132120123001102213 |
5 | 220130021410101300312 |
6 | 2133220550353424251 |
7 | 66316366032060151 |
oct | 6424363033012247 |
9 | 1104655301588484 |
10 | 230105430103207 |
11 | 6735618a5033aa |
12 | 21983b82b6b087 |
13 | 9b51b061ba989 |
14 | 40b723b291ad1 |
15 | 1b90884b673a7 |
hex | d147986c14a7 |
230105430103207 has 2 divisors, whose sum is σ = 230105430103208. Its totient is φ = 230105430103206.
The previous prime is 230105430103193. The next prime is 230105430103277. The reversal of 230105430103207 is 702301034501032.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 230105430103207 - 231 = 230103282619559 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (230105430103277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115052715051603 + 115052715051604.
It is an arithmetic number, because the mean of its divisors is an integer number (115052715051604).
Almost surely, 2230105430103207 is an apocalyptic number.
230105430103207 is a deficient number, since it is larger than the sum of its proper divisors (1).
230105430103207 is an equidigital number, since it uses as much as digits as its factorization.
230105430103207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 31.
Adding to 230105430103207 its reverse (702301034501032), we get a palindrome (932406464604239).
The spelling of 230105430103207 in words is "two hundred thirty trillion, one hundred five billion, four hundred thirty million, one hundred three thousand, two hundred seven".
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