Base | Representation |
---|---|
bin | 10101011011110001… |
… | …001000010010010011 |
3 | 2012101220201210110121 |
4 | 111123301020102103 |
5 | 334113144122011 |
6 | 14323411211111 |
7 | 1443214346632 |
oct | 253361102223 |
9 | 65356653417 |
10 | 23014442131 |
11 | 984006400a |
12 | 45635a6a97 |
13 | 222a0778c5 |
14 | 11847ab519 |
15 | 8ea713e71 |
hex | 55bc48493 |
23014442131 has 2 divisors, whose sum is σ = 23014442132. Its totient is φ = 23014442130.
The previous prime is 23014442123. The next prime is 23014442147. The reversal of 23014442131 is 13124441032.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23014442131 - 23 = 23014442123 is a prime.
It is a super-2 number, since 2×230144421312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 23014442096 and 23014442105.
It is not a weakly prime, because it can be changed into another prime (23014442431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11507221065 + 11507221066.
It is an arithmetic number, because the mean of its divisors is an integer number (11507221066).
Almost surely, 223014442131 is an apocalyptic number.
23014442131 is a deficient number, since it is larger than the sum of its proper divisors (1).
23014442131 is an equidigital number, since it uses as much as digits as its factorization.
23014442131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 23014442131 its reverse (13124441032), we get a palindrome (36138883163).
The spelling of 23014442131 in words is "twenty-three billion, fourteen million, four hundred forty-two thousand, one hundred thirty-one".
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