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23023341113441 is a prime number
BaseRepresentation
bin1010011110000100010100…
…00100011001000001100001
310000112000021020011012100212
411033002022010121001201
511004203300311112231
6120544435450423505
74564244566331264
oct517021204310141
9100460236135325
1023023341113441
117377164928809
1226ba0b2431b95
13cb0126767166
1459849b078cdb
1529dd5381a42b
hex14f08a119061

23023341113441 has 2 divisors, whose sum is σ = 23023341113442. Its totient is φ = 23023341113440.

The previous prime is 23023341113413. The next prime is 23023341113447. The reversal of 23023341113441 is 14431114332032.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15171772849216 + 7851568264225 = 3895096^2 + 2802065^2 .

It is a cyclic number.

It is not a de Polignac number, because 23023341113441 - 218 = 23023340851297 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 23023341113398 and 23023341113407.

It is not a weakly prime, because it can be changed into another prime (23023341113447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11511670556720 + 11511670556721.

It is an arithmetic number, because the mean of its divisors is an integer number (11511670556721).

Almost surely, 223023341113441 is an apocalyptic number.

It is an amenable number.

23023341113441 is a deficient number, since it is larger than the sum of its proper divisors (1).

23023341113441 is an equidigital number, since it uses as much as digits as its factorization.

23023341113441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20736, while the sum is 32.

Adding to 23023341113441 its reverse (14431114332032), we get a palindrome (37454455445473).

The spelling of 23023341113441 in words is "twenty-three trillion, twenty-three billion, three hundred forty-one million, one hundred thirteen thousand, four hundred forty-one".