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230301320119 = 1317715486163
BaseRepresentation
bin1101011001111100000…
…1110100001110110111
3211000110002120020100221
43112133001310032313
512233124114220434
6253444324315211
722432036631113
oct3263701641667
9730402506327
10230301320119
1189741100522
1238773542b07
1318942c54bb0
14b20a564743
155ecd76d2b4
hex359f0743b7

230301320119 has 4 divisors (see below), whose sum is σ = 248016806296. Its totient is φ = 212585833944.

The previous prime is 230301320113. The next prime is 230301320153. The reversal of 230301320119 is 911023103032.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 230301320119 - 213 = 230301311927 is a prime.

It is a super-3 number, since 3×2303013201193 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 230301320093 and 230301320102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (230301320113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8857743069 + ... + 8857743094.

It is an arithmetic number, because the mean of its divisors is an integer number (62004201574).

Almost surely, 2230301320119 is an apocalyptic number.

230301320119 is a deficient number, since it is larger than the sum of its proper divisors (17715486177).

230301320119 is a wasteful number, since it uses less digits than its factorization.

230301320119 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17715486176.

The product of its (nonzero) digits is 972, while the sum is 25.

The spelling of 230301320119 in words is "two hundred thirty billion, three hundred one million, three hundred twenty thousand, one hundred nineteen".

Divisors: 1 13 17715486163 230301320119