Base | Representation |
---|---|
bin | 1010011110010011001110… |
… | …00001101101001000111111 |
3 | 10000112202220220101100011012 |
4 | 11033021213001231020333 |
5 | 11004321142321011224 |
6 | 120552241501545435 |
7 | 4564650103416053 |
oct | 517114701551077 |
9 | 100482826340135 |
10 | 23031343141439 |
11 | 737a5a0860896 |
12 | 26bb76627527b |
13 | cb0b0053a379 |
14 | 598a19b0dc63 |
15 | 29e1710b680e |
hex | 14f26706d23f |
23031343141439 has 2 divisors, whose sum is σ = 23031343141440. Its totient is φ = 23031343141438.
The previous prime is 23031343141427. The next prime is 23031343141483. The reversal of 23031343141439 is 93414134313032.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23031343141439 - 24 = 23031343141423 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 23031343141396 and 23031343141405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23031343141489) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11515671570719 + 11515671570720.
It is an arithmetic number, because the mean of its divisors is an integer number (11515671570720).
Almost surely, 223031343141439 is an apocalyptic number.
23031343141439 is a deficient number, since it is larger than the sum of its proper divisors (1).
23031343141439 is an equidigital number, since it uses as much as digits as its factorization.
23031343141439 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 279936, while the sum is 41.
The spelling of 23031343141439 in words is "twenty-three trillion, thirty-one billion, three hundred forty-three million, one hundred forty-one thousand, four hundred thirty-nine".
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