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2304013147 is a prime number
BaseRepresentation
bin1000100101010100…
…0111001101011011
312221120101222212021
42021111013031123
514204311410042
61020342555311
7111044534332
oct21125071533
95846358767
102304013147
11a826121a7
12543738b37
132a944b9b7
1417bdd4d19
15d7415867
hex8954735b

2304013147 has 2 divisors, whose sum is σ = 2304013148. Its totient is φ = 2304013146.

The previous prime is 2304013133. The next prime is 2304013171. The reversal of 2304013147 is 7413104032.

2304013147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2304013147 - 215 = 2303980379 is a prime.

It is not a weakly prime, because it can be changed into another prime (2304011147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1152006573 + 1152006574.

It is an arithmetic number, because the mean of its divisors is an integer number (1152006574).

Almost surely, 22304013147 is an apocalyptic number.

2304013147 is a deficient number, since it is larger than the sum of its proper divisors (1).

2304013147 is an equidigital number, since it uses as much as digits as its factorization.

2304013147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 25.

The square root of 2304013147 is about 48000.1369477213. The cubic root of 2304013147 is about 1320.7734117312.

Adding to 2304013147 its reverse (7413104032), we get a palindrome (9717117179).

The spelling of 2304013147 in words is "two billion, three hundred four million, thirteen thousand, one hundred forty-seven".