Base | Representation |
---|---|
bin | 100001100001110011000… |
… | …010101100000001101001 |
3 | 22011021002222201220101021 |
4 | 201201303002230001221 |
5 | 300222124313230423 |
6 | 4522242525452441 |
7 | 325314034404022 |
oct | 41416302540151 |
9 | 8137088656337 |
10 | 2304032555113 |
11 | 809153347463 |
12 | 312653a11121 |
13 | 139366972663 |
14 | 7d7313bbc49 |
15 | 3edee6e295d |
hex | 218730ac069 |
2304032555113 has 2 divisors, whose sum is σ = 2304032555114. Its totient is φ = 2304032555112.
The previous prime is 2304032555087. The next prime is 2304032555129. The reversal of 2304032555113 is 3115552304032.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1330984464489 + 973048090624 = 1153683^2 + 986432^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2304032555113 is a prime.
It is not a weakly prime, because it can be changed into another prime (2304032505113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1152016277556 + 1152016277557.
It is an arithmetic number, because the mean of its divisors is an integer number (1152016277557).
Almost surely, 22304032555113 is an apocalyptic number.
It is an amenable number.
2304032555113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2304032555113 is an equidigital number, since it uses as much as digits as its factorization.
2304032555113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54000, while the sum is 34.
Adding to 2304032555113 its reverse (3115552304032), we get a palindrome (5419584859145).
The spelling of 2304032555113 in words is "two trillion, three hundred four billion, thirty-two million, five hundred fifty-five thousand, one hundred thirteen".
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