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23041311314053 is a prime number
BaseRepresentation
bin1010011110100101110010…
…01011010001000010000101
310000120201122121020222022111
411033102321023101002011
511010002101144022203
6121001010550301021
74565452113451564
oct517227113210205
9100521577228274
1023041311314053
11738384660747a
122701688657771
13cb1a2b762b66
145992c3949bdb
1529e55628926d
hex14f4b92d1085

23041311314053 has 2 divisors, whose sum is σ = 23041311314054. Its totient is φ = 23041311314052.

The previous prime is 23041311314011. The next prime is 23041311314069. The reversal of 23041311314053 is 35041311314032.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 16080404761444 + 6960906552609 = 4010038^2 + 2638353^2 .

It is a cyclic number.

It is not a de Polignac number, because 23041311314053 - 233 = 23032721379461 is a prime.

It is a super-2 number, since 2×230413113140532 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23041311314003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11520655657026 + 11520655657027.

It is an arithmetic number, because the mean of its divisors is an integer number (11520655657027).

Almost surely, 223041311314053 is an apocalyptic number.

It is an amenable number.

23041311314053 is a deficient number, since it is larger than the sum of its proper divisors (1).

23041311314053 is an equidigital number, since it uses as much as digits as its factorization.

23041311314053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 23041311314053 its reverse (35041311314032), we get a palindrome (58082622628085).

The spelling of 23041311314053 in words is "twenty-three trillion, forty-one billion, three hundred eleven million, three hundred fourteen thousand, fifty-three".