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23042412425317 is a prime number
BaseRepresentation
bin1010011110100111110101…
…10011101011000001100101
310000120211111100012020000011
411033103322303223001211
511010011330040102232
6121001312123050221
74565521313653525
oct517237263530145
9100524440166004
1023042412425317
11738426111068a
122701935370971
13cb1b7591259c
14599389c97685
1529e5bcc8e547
hex14f4faceb065

23042412425317 has 2 divisors, whose sum is σ = 23042412425318. Its totient is φ = 23042412425316.

The previous prime is 23042412425309. The next prime is 23042412425353. The reversal of 23042412425317 is 71352421424032.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 16912499975361 + 6129912449956 = 4112481^2 + 2475866^2 .

It is a cyclic number.

It is not a de Polignac number, because 23042412425317 - 23 = 23042412425309 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 23042412425317.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23042412425377) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11521206212658 + 11521206212659.

It is an arithmetic number, because the mean of its divisors is an integer number (11521206212659).

Almost surely, 223042412425317 is an apocalyptic number.

It is an amenable number.

23042412425317 is a deficient number, since it is larger than the sum of its proper divisors (1).

23042412425317 is an equidigital number, since it uses as much as digits as its factorization.

23042412425317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 322560, while the sum is 40.

Adding to 23042412425317 its reverse (71352421424032), we get a palindrome (94394833849349).

The spelling of 23042412425317 in words is "twenty-three trillion, forty-two billion, four hundred twelve million, four hundred twenty-five thousand, three hundred seventeen".