Base | Representation |
---|---|
bin | 1101011010101111100… |
… | …0101101000001111011 |
3 | 211001000010110200201211 |
4 | 3112223320231001323 |
5 | 12234044330111011 |
6 | 253521552023551 |
7 | 22440266316625 |
oct | 3265370550173 |
9 | 731003420654 |
10 | 230517035131 |
11 | 89841947399 |
12 | 38813831bb7 |
13 | 18978852106 |
14 | b22b077c15 |
15 | 5ee267db21 |
hex | 35abe2d07b |
230517035131 has 2 divisors, whose sum is σ = 230517035132. Its totient is φ = 230517035130.
The previous prime is 230517035123. The next prime is 230517035137. The reversal of 230517035131 is 131530715032.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 230517035131 - 23 = 230517035123 is a prime.
It is a super-2 number, since 2×2305170351312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 230517035093 and 230517035102.
It is not a weakly prime, because it can be changed into another prime (230517035137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115258517565 + 115258517566.
It is an arithmetic number, because the mean of its divisors is an integer number (115258517566).
Almost surely, 2230517035131 is an apocalyptic number.
230517035131 is a deficient number, since it is larger than the sum of its proper divisors (1).
230517035131 is an equidigital number, since it uses as much as digits as its factorization.
230517035131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9450, while the sum is 31.
The spelling of 230517035131 in words is "two hundred thirty billion, five hundred seventeen million, thirty-five thousand, one hundred thirty-one".
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