Base | Representation |
---|---|
bin | 100001100011000111000… |
… | …000011001010010010101 |
3 | 22011101202011102112001111 |
4 | 201203013000121102111 |
5 | 300233020424141323 |
6 | 4523034410455021 |
7 | 325363661131456 |
oct | 41430700312225 |
9 | 8141664375044 |
10 | 2305441240213 |
11 | 809806528421 |
12 | 312987734471 |
13 | 13952c772337 |
14 | 7d82651112d |
15 | 3ee83200c0d |
hex | 218c7019495 |
2305441240213 has 2 divisors, whose sum is σ = 2305441240214. Its totient is φ = 2305441240212.
The previous prime is 2305441240187. The next prime is 2305441240243. The reversal of 2305441240213 is 3120421445032.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2292916720644 + 12524519569 = 1514238^2 + 111913^2 .
It is a cyclic number.
It is not a de Polignac number, because 2305441240213 - 237 = 2168002286741 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2305441240243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1152720620106 + 1152720620107.
It is an arithmetic number, because the mean of its divisors is an integer number (1152720620107).
Almost surely, 22305441240213 is an apocalyptic number.
It is an amenable number.
2305441240213 is a deficient number, since it is larger than the sum of its proper divisors (1).
2305441240213 is an equidigital number, since it uses as much as digits as its factorization.
2305441240213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 2305441240213 its reverse (3120421445032), we get a palindrome (5425862685245).
The spelling of 2305441240213 in words is "two trillion, three hundred five billion, four hundred forty-one million, two hundred forty thousand, two hundred thirteen".
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