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23100044012813 is a prime number
BaseRepresentation
bin1010100000010011001011…
…11010101110110100001101
310000210100020210012012120202
411100021211322232310031
511011432342231402223
6121044002544023245
74602631424244515
oct520114572566415
9100710223165522
1023100044012813
1173a67456a0339
122710b3a001b25
13cb742b793551
1459c095d90845
152a0d4260a428
hex150265eaed0d

23100044012813 has 2 divisors, whose sum is σ = 23100044012814. Its totient is φ = 23100044012812.

The previous prime is 23100044012761. The next prime is 23100044012849. The reversal of 23100044012813 is 31821044000132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14593179290404 + 8506864722409 = 3820102^2 + 2916653^2 .

It is a cyclic number.

It is not a de Polignac number, because 23100044012813 - 28 = 23100044012557 is a prime.

It is a super-2 number, since 2×231000440128132 (a number of 28 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23100044012863) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11550022006406 + 11550022006407.

It is an arithmetic number, because the mean of its divisors is an integer number (11550022006407).

Almost surely, 223100044012813 is an apocalyptic number.

It is an amenable number.

23100044012813 is a deficient number, since it is larger than the sum of its proper divisors (1).

23100044012813 is an equidigital number, since it uses as much as digits as its factorization.

23100044012813 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 23100044012813 its reverse (31821044000132), we get a palindrome (54921088012945).

The spelling of 23100044012813 in words is "twenty-three trillion, one hundred billion, forty-four million, twelve thousand, eight hundred thirteen".