Base | Representation |
---|---|
bin | 1010100000010100000010… |
… | …10011100101110000000111 |
3 | 10000210101102210211021212122 |
4 | 11100022001103211300013 |
5 | 11011434312344422434 |
6 | 121044120320440155 |
7 | 4602646004035463 |
oct | 520120123456007 |
9 | 100711383737778 |
10 | 23100503514119 |
11 | 73a6961006489 |
12 | 2711047a7905b |
13 | cb74a2a38b05 |
14 | 59c0db0034a3 |
15 | 2a0d6cb23c2e |
hex | 1502814e5c07 |
23100503514119 has 2 divisors, whose sum is σ = 23100503514120. Its totient is φ = 23100503514118.
The previous prime is 23100503514043. The next prime is 23100503514133. The reversal of 23100503514119 is 91141530500132.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-23100503514119 is a prime.
It is a super-2 number, since 2×231005035141192 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23100503511119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11550251757059 + 11550251757060.
It is an arithmetic number, because the mean of its divisors is an integer number (11550251757060).
Almost surely, 223100503514119 is an apocalyptic number.
23100503514119 is a deficient number, since it is larger than the sum of its proper divisors (1).
23100503514119 is an equidigital number, since it uses as much as digits as its factorization.
23100503514119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16200, while the sum is 35.
The spelling of 23100503514119 in words is "twenty-three trillion, one hundred billion, five hundred three million, five hundred fourteen thousand, one hundred nineteen".
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