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231011113133 is a prime number
BaseRepresentation
bin1101011100100101010…
…1011101100010101101
3211002021120011110100002
43113021111131202231
512241102321110013
6254043001514045
722455446030363
oct3271125354255
9732246143302
10231011113133
1189a75829519
12389311a2925
1318a27012868
14b27692b633
156020c27358
hex35c955d8ad

231011113133 has 2 divisors, whose sum is σ = 231011113134. Its totient is φ = 231011113132.

The previous prime is 231011113063. The next prime is 231011113147. The reversal of 231011113133 is 331311110132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 195281796649 + 35729316484 = 441907^2 + 189022^2 .

It is a cyclic number.

It is not a de Polignac number, because 231011113133 - 224 = 230994335917 is a prime.

It is a super-2 number, since 2×2310111131332 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (231011113633) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115505556566 + 115505556567.

It is an arithmetic number, because the mean of its divisors is an integer number (115505556567).

Almost surely, 2231011113133 is an apocalyptic number.

It is an amenable number.

231011113133 is a deficient number, since it is larger than the sum of its proper divisors (1).

231011113133 is an equidigital number, since it uses as much as digits as its factorization.

231011113133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 231011113133 its reverse (331311110132), we get a palindrome (562322223265).

The spelling of 231011113133 in words is "two hundred thirty-one billion, eleven million, one hundred thirteen thousand, one hundred thirty-three".