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23102113 is a prime number
BaseRepresentation
bin101100000100…
…0001010100001
31121110201010211
41120020022201
521403231423
62143054121
7400236046
oct130101241
947421124
1023102113
1112049a61
1278a1341
134a2b3b8
1430d51cd
15206510d
hex16082a1

23102113 has 2 divisors, whose sum is σ = 23102114. Its totient is φ = 23102112.

The previous prime is 23102111. The next prime is 23102129. The reversal of 23102113 is 31120132.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13417569 + 9684544 = 3663^2 + 3112^2 .

It is a cyclic number.

It is not a de Polignac number, because 23102113 - 21 = 23102111 is a prime.

Together with 23102111, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 23102093 and 23102102.

It is not a weakly prime, because it can be changed into another prime (23102111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11551056 + 11551057.

It is an arithmetic number, because the mean of its divisors is an integer number (11551057).

Almost surely, 223102113 is an apocalyptic number.

It is an amenable number.

23102113 is a deficient number, since it is larger than the sum of its proper divisors (1).

23102113 is an equidigital number, since it uses as much as digits as its factorization.

23102113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 23102113 is about 4806.4657493838. The cubic root of 23102113 is about 284.8069401438.

Adding to 23102113 its reverse (31120132), we get a palindrome (54222245).

The spelling of 23102113 in words is "twenty-three million, one hundred two thousand, one hundred thirteen".