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23104021131 = 3243531126421
BaseRepresentation
bin10101100001000110…
…110110001010001011
32012122011021212202100
4111201012312022023
5334304112134011
614340331204443
71445352640122
oct254106661213
965564255670
1023104021131
119886688044
1245895a6723
1322427b0029
141192648ab9
1590350ad56
hex5611b628b

23104021131 has 24 divisors (see below), whose sum is σ = 34792922736. Its totient is φ = 14760607680.

The previous prime is 23104021121. The next prime is 23104021133. The reversal of 23104021131 is 13112040132.

23104021131 is a `hidden beast` number, since 231 + 0 + 402 + 1 + 1 + 31 = 666.

It is not a de Polignac number, because 23104021131 - 217 = 23103890059 is a prime.

It is a super-2 number, since 2×231040211312 (a number of 22 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (23104021133) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 542700 + ... + 583721.

It is an arithmetic number, because the mean of its divisors is an integer number (1449705114).

Almost surely, 223104021131 is an apocalyptic number.

23104021131 is a deficient number, since it is larger than the sum of its proper divisors (11688901605).

23104021131 is a wasteful number, since it uses less digits than its factorization.

23104021131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1126523 (or 1126520 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 23104021131 its reverse (13112040132), we get a palindrome (36216061263).

The spelling of 23104021131 in words is "twenty-three billion, one hundred four million, twenty-one thousand, one hundred thirty-one".

Divisors: 1 3 9 43 53 129 159 387 477 2279 6837 20511 1126421 3379263 10137789 48436103 59700313 145308309 179100939 435924927 537302817 2567113459 7701340377 23104021131