231043313041 has 2 divisors, whose sum is σ = 231043313042. Its totient is φ = 231043313040.

The previous prime is 231043312987. The next prime is 231043313047. The reversal of 231043313041 is 140313340132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 187485536016 + 43557777025 = 432996^2 + 208705^2 .

It is a cyclic number.

It is not a de Polignac number, because 231043313041 - 2³³ = 222453378449 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 231043312997 and 231043313015.

It is not a weakly prime, because it can be changed into another prime (231043313047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115521656520 + 115521656521.

It is an arithmetic number, because the mean of its divisors is an integer number (115521656521).

Almost surely, 2^231043313041 is an apocalyptic number.

It is an amenable number.

231043313041 is a deficient number, since it is larger than the sum of its proper divisors (1).

231043313041 is an equidigital number, since it uses as much as digits as its factorization.

231043313041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 231043313041 its reverse (140313340132), we get a palindrome (371356653173).

The spelling of 231043313041 in words is "two hundred thirty-one billion, forty-three million, three hundred thirteen thousand, forty-one".