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23105113 is a prime number
BaseRepresentation
bin101100000100…
…0111001011001
31121110212020221
41120020321121
521403330423
62143120041
7400250563
oct130107131
947425227
1023105113
1112051239
1278a3021
134a2c885
1430d6333
152065e5d
hex1608e59

23105113 has 2 divisors, whose sum is σ = 23105114. Its totient is φ = 23105112.

The previous prime is 23105107. The next prime is 23105119. The reversal of 23105113 is 31150132.

It is a balanced prime because it is at equal distance from previous prime (23105107) and next prime (23105119).

It can be written as a sum of positive squares in only one way, i.e., 18766224 + 4338889 = 4332^2 + 2083^2 .

It is a cyclic number.

It is not a de Polignac number, because 23105113 - 217 = 22974041 is a prime.

It is not a weakly prime, because it can be changed into another prime (23105119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11552556 + 11552557.

It is an arithmetic number, because the mean of its divisors is an integer number (11552557).

Almost surely, 223105113 is an apocalyptic number.

It is an amenable number.

23105113 is a deficient number, since it is larger than the sum of its proper divisors (1).

23105113 is an equidigital number, since it uses as much as digits as its factorization.

23105113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90, while the sum is 16.

The square root of 23105113 is about 4806.7778188720. Note that the first 3 decimals coincide. The cubic root of 23105113 is about 284.8192677873.

Adding to 23105113 its reverse (31150132), we get a palindrome (54255245).

The spelling of 23105113 in words is "twenty-three million, one hundred five thousand, one hundred thirteen".