Base | Representation |
---|---|
bin | 100001101000010100010… |
… | …000101011000010001001 |
3 | 22011221011211000210211201 |
4 | 201220110100223002021 |
5 | 300330443233221022 |
6 | 4525401255024201 |
7 | 325652351414152 |
oct | 41502420530211 |
9 | 8157154023751 |
10 | 2311032320137 |
11 | 811115550532 |
12 | 313a8806b061 |
13 | 139c10bc5658 |
14 | 7dbd6cb6929 |
15 | 401adeb2127 |
hex | 21a1442b089 |
2311032320137 has 2 divisors, whose sum is σ = 2311032320138. Its totient is φ = 2311032320136.
The previous prime is 2311032320131. The next prime is 2311032320239. The reversal of 2311032320137 is 7310232301132.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2272583385081 + 38448935056 = 1507509^2 + 196084^2 .
It is a cyclic number.
It is not a de Polignac number, because 2311032320137 - 223 = 2311023931529 is a prime.
It is not a weakly prime, because it can be changed into another prime (2311032320131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1155516160068 + 1155516160069.
It is an arithmetic number, because the mean of its divisors is an integer number (1155516160069).
Almost surely, 22311032320137 is an apocalyptic number.
It is an amenable number.
2311032320137 is a deficient number, since it is larger than the sum of its proper divisors (1).
2311032320137 is an equidigital number, since it uses as much as digits as its factorization.
2311032320137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4536, while the sum is 28.
Adding to 2311032320137 its reverse (7310232301132), we get a palindrome (9621264621269).
The spelling of 2311032320137 in words is "two trillion, three hundred eleven billion, thirty-two million, three hundred twenty thousand, one hundred thirty-seven".
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