Base | Representation |
---|---|
bin | 100001101000011010001… |
… | …100111110001000100001 |
3 | 22011221102202121201212021 |
4 | 201220122030332020201 |
5 | 300331144243404324 |
6 | 4525415215501441 |
7 | 325655001660154 |
oct | 41503214761041 |
9 | 8157382551767 |
10 | 2311132013089 |
11 | 8111668522a9 |
12 | 313ab5527881 |
13 | 139c2875c473 |
14 | 7dc06227c9b |
15 | 401b7b05ae4 |
hex | 21a1a33e221 |
2311132013089 has 2 divisors, whose sum is σ = 2311132013090. Its totient is φ = 2311132013088.
The previous prime is 2311132013081. The next prime is 2311132013107. The reversal of 2311132013089 is 9803102311132.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1954683610000 + 356448403089 = 1398100^2 + 597033^2 .
It is a cyclic number.
It is not a de Polignac number, because 2311132013089 - 23 = 2311132013081 is a prime.
It is not a weakly prime, because it can be changed into another prime (2311132013081) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1155566006544 + 1155566006545.
It is an arithmetic number, because the mean of its divisors is an integer number (1155566006545).
Almost surely, 22311132013089 is an apocalyptic number.
It is an amenable number.
2311132013089 is a deficient number, since it is larger than the sum of its proper divisors (1).
2311132013089 is an equidigital number, since it uses as much as digits as its factorization.
2311132013089 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7776, while the sum is 34.
The spelling of 2311132013089 in words is "two trillion, three hundred eleven billion, one hundred thirty-two million, thirteen thousand, eighty-nine".
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