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23112400413227 is a prime number
BaseRepresentation
bin1010100000101010001100…
…11010101010001000101011
310000211112010220221101101112
411100111012122222020223
511012133144001210402
6121053405024340535
74603546554023516
oct520250632521053
9100745126841345
1023112400413227
117400a06548904
12271340817474b
13cb864a712598
1459c909063d7d
152a13172cae52
hex1505466aa22b

23112400413227 has 2 divisors, whose sum is σ = 23112400413228. Its totient is φ = 23112400413226.

The previous prime is 23112400413191. The next prime is 23112400413257. The reversal of 23112400413227 is 72231400421132.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 23112400413227 - 218 = 23112400151083 is a prime.

It is a super-2 number, since 2×231124004132272 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 23112400413193 and 23112400413202.

It is not a weakly prime, because it can be changed into another prime (23112400413257) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11556200206613 + 11556200206614.

It is an arithmetic number, because the mean of its divisors is an integer number (11556200206614).

Almost surely, 223112400413227 is an apocalyptic number.

23112400413227 is a deficient number, since it is larger than the sum of its proper divisors (1).

23112400413227 is an equidigital number, since it uses as much as digits as its factorization.

23112400413227 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16128, while the sum is 32.

Adding to 23112400413227 its reverse (72231400421132), we get a palindrome (95343800834359).

The spelling of 23112400413227 in words is "twenty-three trillion, one hundred twelve billion, four hundred million, four hundred thirteen thousand, two hundred twenty-seven".