23112564430117 has 2 divisors, whose sum is σ = 23112564430118. Its totient is φ = 23112564430116.

The previous prime is 23112564430093. The next prime is 23112564430279. The reversal of 23112564430117 is 71103446521132.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 20284133371681 + 2828431058436 = 4503791^2 + 1681794^2 .

It is a cyclic number.

It is not a de Polignac number, because 23112564430117 - 2¹¹ = 23112564428069 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 23112564430117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23112564430717) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11556282215058 + 11556282215059.

It is an arithmetic number, because the mean of its divisors is an integer number (11556282215059).

Almost surely, 2^{23112564430117} is an apocalyptic number.

It is an amenable number.

23112564430117 is a deficient number, since it is larger than the sum of its proper divisors (1).

23112564430117 is an equidigital number, since it uses as much as digits as its factorization.

23112564430117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120960, while the sum is 40.

The spelling of 23112564430117 in words is "twenty-three trillion, one hundred twelve billion, five hundred sixty-four million, four hundred thirty thousand, one hundred seventeen".