Base | Representation |
---|---|
bin | 110100100011011000101011… |
… | …100101011110011010101011 |
3 | 1010022100211012011022121221002 |
4 | 310203120223211132122223 |
5 | 220243313421413424042 |
6 | 2135323411441505215 |
7 | 66453412242453143 |
oct | 6443305345363253 |
9 | 1108324164277832 |
10 | 231130101311147 |
11 | 677107a8705a45 |
12 | 21b0a68b34220b |
13 | 9bc76238509bc |
14 | 4110a84135923 |
15 | 1bac3572a6132 |
hex | d2362b95e6ab |
231130101311147 has 2 divisors, whose sum is σ = 231130101311148. Its totient is φ = 231130101311146.
The previous prime is 231130101311101. The next prime is 231130101311171. The reversal of 231130101311147 is 741113101031132.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 231130101311147 - 216 = 231130101245611 is a prime.
It is a super-2 number, since 2×2311301013111472 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (231130101311647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115565050655573 + 115565050655574.
It is an arithmetic number, because the mean of its divisors is an integer number (115565050655574).
Almost surely, 2231130101311147 is an apocalyptic number.
231130101311147 is a deficient number, since it is larger than the sum of its proper divisors (1).
231130101311147 is an equidigital number, since it uses as much as digits as its factorization.
231130101311147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 29.
Adding to 231130101311147 its reverse (741113101031132), we get a palindrome (972243202342279).
The spelling of 231130101311147 in words is "two hundred thirty-one trillion, one hundred thirty billion, one hundred one million, three hundred eleven thousand, one hundred forty-seven".
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