Base | Representation |
---|---|
bin | 100001101000100100010… |
… | …010110000000011000111 |
3 | 22011221212120011102102112 |
4 | 201220210102300003013 |
5 | 300332021113103143 |
6 | 4525444104131235 |
7 | 325662125620223 |
oct | 41504422600307 |
9 | 8157776142375 |
10 | 2311301300423 |
11 | 811243368395 |
12 | 313b42166b1b |
13 | 139c5485229b |
14 | 7dc208d3783 |
15 | 401c78e4e18 |
hex | 21a244b00c7 |
2311301300423 has 2 divisors, whose sum is σ = 2311301300424. Its totient is φ = 2311301300422.
The previous prime is 2311301300393. The next prime is 2311301300443. The reversal of 2311301300423 is 3240031031132.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2311301300423 - 226 = 2311234191559 is a prime.
It is a super-2 number, since 2×23113013004232 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2311301300443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1155650650211 + 1155650650212.
It is an arithmetic number, because the mean of its divisors is an integer number (1155650650212).
Almost surely, 22311301300423 is an apocalyptic number.
2311301300423 is a deficient number, since it is larger than the sum of its proper divisors (1).
2311301300423 is an equidigital number, since it uses as much as digits as its factorization.
2311301300423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 2311301300423 its reverse (3240031031132), we get a palindrome (5551332331555).
The spelling of 2311301300423 in words is "two trillion, three hundred eleven billion, three hundred one million, three hundred thousand, four hundred twenty-three".
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