Base | Representation |
---|---|
bin | 100001101000100100111… |
… | …000100011101100100111 |
3 | 22011221220020210221121011 |
4 | 201220210320203230213 |
5 | 300332031132230203 |
6 | 4525445100403051 |
7 | 325662306066013 |
oct | 41504470435447 |
9 | 8157806727534 |
10 | 2311311211303 |
11 | 811248a175a6 |
12 | 313b45546487 |
13 | 139c56912403 |
14 | 7dc21d53543 |
15 | 401c870176d |
hex | 21a24e23b27 |
2311311211303 has 2 divisors, whose sum is σ = 2311311211304. Its totient is φ = 2311311211302.
The previous prime is 2311311211277. The next prime is 2311311211309. The reversal of 2311311211303 is 3031121131132.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2311311211303 is a prime.
It is a super-2 number, since 2×23113112113032 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2311311211309) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1155655605651 + 1155655605652.
It is an arithmetic number, because the mean of its divisors is an integer number (1155655605652).
Almost surely, 22311311211303 is an apocalyptic number.
2311311211303 is a deficient number, since it is larger than the sum of its proper divisors (1).
2311311211303 is an equidigital number, since it uses as much as digits as its factorization.
2311311211303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 2311311211303 its reverse (3031121131132), we get a palindrome (5342432342435).
The spelling of 2311311211303 in words is "two trillion, three hundred eleven billion, three hundred eleven million, two hundred eleven thousand, three hundred three".
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