Base | Representation |
---|---|
bin | 1010100000101011111010… |
… | …11100001000000111101111 |
3 | 10000211121112020222100012211 |
4 | 11100111331130020013233 |
5 | 11012142041311420241 |
6 | 121054040402311251 |
7 | 4603611463354144 |
oct | 520257534100757 |
9 | 100747466870184 |
10 | 23113323545071 |
11 | 740133a63a491 |
12 | 2713625358527 |
13 | cb8766a47a46 |
14 | 59c9958c23cb |
15 | 2a136d376781 |
hex | 15057d7081ef |
23113323545071 has 2 divisors, whose sum is σ = 23113323545072. Its totient is φ = 23113323545070.
The previous prime is 23113323545057. The next prime is 23113323545129. The reversal of 23113323545071 is 17054532331132.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23113323545071 - 219 = 23113323020783 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23113323545671) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11556661772535 + 11556661772536.
It is an arithmetic number, because the mean of its divisors is an integer number (11556661772536).
Almost surely, 223113323545071 is an apocalyptic number.
23113323545071 is a deficient number, since it is larger than the sum of its proper divisors (1).
23113323545071 is an equidigital number, since it uses as much as digits as its factorization.
23113323545071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 226800, while the sum is 40.
The spelling of 23113323545071 in words is "twenty-three trillion, one hundred thirteen billion, three hundred twenty-three million, five hundred forty-five thousand, seventy-one".
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