Base | Representation |
---|---|
bin | 110100100011100011111111… |
… | …010010011011001000001101 |
3 | 1010022101222112100002102002122 |
4 | 310203203333102123020031 |
5 | 220244013303203140300 |
6 | 2135333140332502325 |
7 | 66454322154342116 |
oct | 6443437722331015 |
9 | 1108358470072078 |
10 | 231142243021325 |
11 | 67715969357569 |
12 | 21b10ab961a9a5 |
13 | 9bc880a1710ac |
14 | 41114b68c120d |
15 | 1bac8181b9c85 |
hex | d238ff49b20d |
231142243021325 has 24 divisors (see below), whose sum is σ = 294376720038240. Its totient is φ = 179907597979200.
The previous prime is 231142243021303. The next prime is 231142243021363. The reversal of 231142243021325 is 523120342241132.
It is not a de Polignac number, because 231142243021325 - 210 = 231142243020301 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 13643090 + ... + 25464060.
It is an arithmetic number, because the mean of its divisors is an integer number (12265696668260).
Almost surely, 2231142243021325 is an apocalyptic number.
231142243021325 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
It is an amenable number.
231142243021325 is a deficient number, since it is larger than the sum of its proper divisors (63234477016915).
231142243021325 is a wasteful number, since it uses less digits than its factorization.
231142243021325 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11842157 (or 11842152 counting only the distinct ones).
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 231142243021325 its reverse (523120342241132), we get a palindrome (754262585262457).
The spelling of 231142243021325 in words is "two hundred thirty-one trillion, one hundred forty-two billion, two hundred forty-three million, twenty-one thousand, three hundred twenty-five".
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