Base | Representation |
---|---|
bin | 1010100000111001010011… |
… | …11000001010111011101111 |
3 | 10000212022002012110120112001 |
4 | 11100130221320022323233 |
5 | 11012301301423420241 |
6 | 121101225534153131 |
7 | 4604254554351313 |
oct | 520345170127357 |
9 | 100768065416461 |
10 | 23120511545071 |
11 | 7404399020256 |
12 | 2714ab06527a7 |
13 | cb9340c95c95 |
14 | 59d0783b9b43 |
15 | 2a163e429431 |
hex | 150729e0aeef |
23120511545071 has 2 divisors, whose sum is σ = 23120511545072. Its totient is φ = 23120511545070.
The previous prime is 23120511545057. The next prime is 23120511545101. The reversal of 23120511545071 is 17054511502132.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23120511545071 - 213 = 23120511536879 is a prime.
It is a super-2 number, since 2×231205115450712 (a number of 28 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 23120511545071.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23120511245071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11560255772535 + 11560255772536.
It is an arithmetic number, because the mean of its divisors is an integer number (11560255772536).
Almost surely, 223120511545071 is an apocalyptic number.
23120511545071 is a deficient number, since it is larger than the sum of its proper divisors (1).
23120511545071 is an equidigital number, since it uses as much as digits as its factorization.
23120511545071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 42000, while the sum is 37.
The spelling of 23120511545071 in words is "twenty-three trillion, one hundred twenty billion, five hundred eleven million, five hundred forty-five thousand, seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •