231213141312133 has 4 divisors (see below), whose sum is σ = 232978127123808. Its totient is φ = 229448155500460.

The previous prime is 231213141312071. The next prime is 231213141312161. The reversal of 231213141312133 is 331213141312132.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 231213141312133 - 2¹³ = 231213141303941 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 231213141312095 and 231213141312104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (231213141112133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 882492905641 + ... + 882492905902.

It is an arithmetic number, because the mean of its divisors is an integer number (58244531780952).

Almost surely, 2^{231213141312133} is an apocalyptic number.

It is an amenable number.

231213141312133 is a deficient number, since it is larger than the sum of its proper divisors (1764985811675).

231213141312133 is a wasteful number, since it uses less digits than its factorization.

231213141312133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1764985811674.

The product of its digits is 7776, while the sum is 31.

Adding to 231213141312133 its reverse (331213141312132), we get a palindrome (562426282624265).

Subtracting 231213141312133 from its reverse (331213141312132), we obtain a palindrome (99999999999999).

The spelling of 231213141312133 in words is "two hundred thirty-one trillion, two hundred thirteen billion, one hundred forty-one million, three hundred twelve thousand, one hundred thirty-three".